Pink Poogle Toy Forum

I used to play this one with my sister, can't remember the name anymore; we got it off one of those "activity kit" type toys that come with a booklet and a bunch of odds and ends.

Anyway, here goes:
Roll 3 1d6
By using simple maths, get as close to 21 as possible without going over. You can only add, subtract, multiply or divide.
edit: I realize you have to post twice in a row, once to roll and a second to make up your formula.

Example:

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Eep, trouble with the dice codes! Anyway, the example is as follows:
Example:

[dice]bmdmwgggpc[/dice]
[dice]dhrycdfcwq[/dice]
[dice]uqsluqjedk[/dice]

let's say you get a 5, 3, and 4

on your succeeding post, you place
5*3+4= 19
(because 5*4+3 is over 21 and so on)

Anyone want to play?

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Surely you can just edit the formula into your post?





Uhhh 5 + 6 + 6 is 17..?

I don't really understand how this works on a forum..

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By WisWis :3

I think I got it...





Edit:
3+4=7
7*3=21!

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Hmm... Let's see





3*(1+1)=6

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It was an honor serving you PPT. I will miss you.
Click here to join my new werewolf forum!

Mmm... 6 isn't really close to 21, now is it?
Let's give this another go.





(6*3)+3=21

Edit: This is too easy. Is there some way to make it more difficult?

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o_o

Well, anyway, 4*4=16+3=19 (I don't think we can repeat numbers...)

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I need a new sig. >_>

Ah, that would make things somewhat more difficult already.





6+4+1=11?

If you can use anything besides simple math... 4²+6-1= 21

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(6*4)-6=18

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It was an honor serving you PPT. I will miss you.
Click here to join my new werewolf forum!

Pardona: I don't think we can use anything beside simple math. Also, 4(6-1)=20





Well, via a bit of cheating...

6=3*2
6=3*2

3*3=9*2=18+3=21-2=19

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I need a new sig. >_>

5*5-5=20

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(3+1)*5=20

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(5+2)*3=21

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Blue graffitied on my signature... But it made me laugh, so it's all good!

3(3+1) = 12

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you're right... not working very well in a forum... how's about whoever gets 21 gets to change the dice and number to aim for? Would that be better?





er... 6+6+6=18...

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